App-Development-with-Swift-Certified-User App Development with Swift Certified User Exam Questions and Answers

This question belongs to View Building with SwiftUI , specifically the objective on positioning and laying out a single SwiftUI view with standard views and modifiers.

The correct answer is D because it uses the right combination of SwiftUI image modifiers for all three requirements:

the image is made resizable with .resizable()

it is given rounded corners with .clipShape(RoundedRectangle(cornerRadius: 50))

it displays the entire image with .aspectRatio(contentMode: .fit)

it is sized with .frame(width: 300)

The key part is .aspectRatio(contentMode: .fit) . In SwiftUI, .fit scales the image so the whole image remains visible inside the available frame. That matches the requirement “displays the entire image, regardless of size.” By contrast, .fill may crop part of the image, so options using .fill do not satisfy the requirement.

Why the others are wrong:

Option A uses .fill, so the full image may not remain visible.

Option B uses invalid modifiers such as .sizablc() and .size(width: 300), and also uses Rectangle(cornerRadius: 50), which is not the correct rounded-rectangle shape syntax.

Option C also uses invalid syntax and .fill, which can crop the image.

Option D uses valid SwiftUI syntax and the correct content mode.

So the correct choice is D , because it is the only option that correctly creates a 300-width image with rounded corners while ensuring the entire image is shown.

You can treat a NavigationLink like a button, and run some Swift code when it is pressed. — False

NavigationSplitView can be used to do navigation differently on different device sizes. — True

You can put a header on your present View in a NavigationStack using .navigationTitle. — True

If you have a NavigationLink that goes to another View with a NavigationLink, you need to declare a NavigationStack at each level. — False

This question belongs to View Building with SwiftUI , specifically the objective on creating a multi-view app with navigation stacks, links, and sheets . Statement 1 is False because NavigationLink is primarily a navigation control that pushes or presents a destination in a navigation container; Apple documents it as creating a navigation link that presents a destination, not as a general-purpose action control like Button.

Statement 2 is True because NavigationSplitView is designed for adaptive navigation and can present navigation in different ways depending on platform and available space. Apple documents NavigationSplitView as a container for navigation across multiple columns, and this adaptive behavior is exactly why it is used differently across device sizes.

Statement 3 is True because .navigationTitle(...) sets the navigation title for a view shown inside a navigation container. Apple explicitly describes a view’s navigation title as something used to visually display the current navigation state of an interface.

Statement 4 is False because you do not need a separate NavigationStack at every level. Apple describes NavigationStack as the container that manages a stack of views, and NavigationLink pushes additional destinations onto that stack. Nested destinations can keep navigating within the same stack.

This question belongs to View Building with SwiftUI , specifically the domain on creating a multi-view app with navigation stacks, links, and sheets .

To present a modal view in SwiftUI when a Boolean state changes, the correct modifier is .sheet . The matching sheet API for a Boolean binding is:

sheet(isPresented: $showInfo) {

// modal content

}

So the first blank must be .sheet , and the second blank must be (isPresented: .

The logic works like this:

@State stores the local Boolean that controls presentation.

Pressing the button calls showInfo.toggle(), changing the value from false to true.

When that Boolean becomes true, the .sheet(isPresented:) modifier presents the modal view.

When the modal is dismissed, SwiftUI updates the Boolean back as needed.

There is also a typing issue in the screenshot: the state variable appears as ShowInfo, while the button and binding use showInfo. Swift is case-sensitive, so those names must match. The corrected code should use the same identifier consistently, such as:

@State var showInfo = false

Therefore, the correct dropdown selections are:

sheet

(isPresented:

This question belongs to View Building with SwiftUI , especially the domain on creating multiple views to implement app logic and sharing values between views. In FirstView, the value typed into the TextField is stored in number, which is a String. When the NavigationLink is tapped, the code passes Int(number) ?? 0 into SecondView. In Swift, converting a string to an integer with Int(...) uses an optional initializer, which means it returns an optional value and will produce nil if the string cannot be converted. The ?? 0 nil-coalescing operator then supplies 0 if conversion fails.

Inside SecondView, the body is:

Color(passedNumber == 3 ? .blue : .red)

This uses the ternary conditional operator. If passedNumber equals 3, the displayed color is blue; otherwise, it is red. Therefore, entering 3 into the TextField causes Int(number) to become 3, which makes the condition passedNumber == 3 true and displays a blue canvas. Any other listed number results in red.

So the correct answer is A. 3 . This matches the SwiftUI pattern of taking user input, converting it to the needed type, passing it into another view, and rendering UI conditionally based on that value.

This question belongs to Swift Programming Language , specifically the objective on managing data using collection types , including dictionaries and arrays . In the dictionary shown, the emojis are the keys and the text descriptions are the values . Swift provides a keys property on dictionaries that returns a collection containing all dictionary keys. To convert that keys collection into an array, you use the Array(...) initializer. Therefore, the correct code is let emojis = Array(faces.keys). Apple documents both the Dictionary.keys property and the Array type used to store a sequence of values of the same type.

Option B is incorrect because faces.values would return the descriptions like " grinning " , " thinking " , and " happy " , not the emoji keys. Options A and C are incorrect because List is a SwiftUI view type, not the correct collection type for creating an array from dictionary contents. Also, the dictionary interface uses properties like .keys and .values, not method calls like .keys() or .values(). Apple’s dictionary documentation makes clear that keys is a property returning a collection of the dictionary’s keys.

Comprehensive and Detailed Explanation From App Development with Swift domains:

This question falls under Swift Programming Language , specifically the domain for managing data using collection types , with emphasis on dictionaries . In Swift, a dictionary stores data as key-value pairs , so in this example the country name is the key and the capital city is the value. To add a new entry, Swift supports two standard approaches. The first is subscript assignment , which is shown in option C : capitalCities[ " Italy " ] = " Rome " . Apple’s documentation explains that you can add a key-value pair to a dictionary by assigning a value for a new key through the dictionary subscript.

The second correct approach is option E : capitalCities.updateValue( " Rome " , forKey: " Italy " ). Apple documents that updateValue(_:forKey:) updates the value for an existing key, or adds a new key-value pair if the key does not already exist . That makes it equally valid for inserting " Italy " : " Rome " into the dictionary.

The incorrect options fail for different reasons. A reverses the key and value, making " Rome " the key and " Italy " the value. B is wrong because append is used with arrays, not dictionaries. D is not the standard valid insertion syntax for Swift dictionaries in this context; Swift’s documented mutation approaches here are subscript assignment and updateValue. Therefore, the two correct answers are C and E .

This question belongs to Swift Programming Language , specifically the domain covering structs, classes, properties, methods, and the difference between structures and classes .

The key point is that Printer is declared as a class :

class Printer {

var copies: Int

init(copies: Int) {

self.copies = copies

}

}

In Swift, classes are reference types . That means when you assign one class instance to another variable, both variables refer to the same object in memory rather than creating a separate copy. Apple’s Swift language guide explains that classes are passed by reference, while structures are value types. So in this code:

var printer1 = Printer(copies: 2)

var printer2 = printer1

both printer1 and printer2 point to the same Printer instance.

Next, this line changes the shared object:

printer2.copies = 10

Because printer2 refers to the same instance as printer1, changing printer2.copies also changes printer1.copies. Therefore, when the code executes:

print(printer1.copies)

the output is 10 .

This question tests one of the most important Swift concepts: classes are reference types , while structs are value types . If Printer had been a struct instead of a class, the result would have been different because assignment would copy the value rather than share the same instance.

RedCircleView()

GreenTriangleView()

BlueSquareView()

BlueSquareView()

GreenTriangleView()

This question belongs to View Building with SwiftUI , specifically arranging views with HStack , VStack , and ZStack . In SwiftUI, an HStack lays views out horizontally, a VStack lays them out vertically, and a ZStack overlays views front-to-back. Apple’s stack layout guidance describes these three containers exactly this way.

To match the canvas, the main HStack must show three items from left to right: a red circle , a green triangle , and then a right-side vertical group. That means the first two blanks inside HStack are RedCircleView() and GreenTriangleView(). On the right side, the VStack shows a blue square on top, so the next blank is BlueSquareView(). Under that, the lower-right shape is made by layering a green triangle on top of a blue square , which means the ZStack must contain BlueSquareView() first as the background and GreenTriangleView() second as the foreground. SwiftUI’s documentation notes that ZStack aligns and overlays its children in depth order, which is why the square goes before the triangle.

So the correct placement order is:

HStack {

RedCircleView()

GreenTriangleView()

VStack {

BlueSquareView()

ZStack {

BlueSquareView()

GreenTriangleView()

}

}

}

That arrangement reproduces the exact layout shown in the canvas.

This question belongs to Xcode Developer Tools , especially the objective on using debugging techniques including breakpoints and stepping controls .

When execution stops at a breakpoint on line 3, Step Over runs that line without entering into another function call, so it is the correct action for moving past line 3 while staying in the current function. Step Into is used when execution reaches line 4 and you want to enter the display(numbers) function, which takes you into the function body starting at line 8. Once inside that function, Step Out continues execution until the current function returns, which is exactly what “step out from line 8” means.

Deactivate breakpoints turns breakpoint handling off so the debugger no longer stops on active breakpoints. Continue program execution resumes the app until the next breakpoint or until the program finishes.

So the correct control order is:

1 = Continue

2 = Deactivate breakpoints

3 = Step Over

4 = Step Into

5 = Step Out